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(F)=-F^2-10F-16
We move all terms to the left:
(F)-(-F^2-10F-16)=0
We get rid of parentheses
F^2+10F+F+16=0
We add all the numbers together, and all the variables
F^2+11F+16=0
a = 1; b = 11; c = +16;
Δ = b2-4ac
Δ = 112-4·1·16
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{57}}{2*1}=\frac{-11-\sqrt{57}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{57}}{2*1}=\frac{-11+\sqrt{57}}{2} $
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